[tex] \frac{cos4x - cos8x}{sin6x} [/tex]
Jawab:
bentuk sederhana dari
[tex]\sf \dfrac{cos~4x - cos~ 8x}{sin~ 6x}=[/tex]
[tex]\sf = \dfrac{- 2 sin \frac{1}{2}(4x+8x) sin \frac{1}{2} (4x-8x)}{sin~ 6x}[/tex]
[tex]\rm = \dfrac{- 2 sin~6x ~.~ sin (-2x)}{sin~ 6x}[/tex]
= - 2 sin (-2x)
= 2 sin (2x)
= 2 sin x cos x
[answer.2.content]
